4=-x^2+3x-8

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Solution for 4=-x^2+3x-8 equation: 



4=-x^2+3x-8

We move all terms to the left:

4-(-x^2+3x-8)=0

We get rid of parentheses

x^2-3x+8+4=0

We add all the numbers together, and all the variables

x^2-3x+12=0

a = 1; b = -3; c = +12;
Δ = b2-4ac
Δ = -32-4·1·12
Δ = -39
Delta is less than zero, so there is no solution for the equation

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